Physics help!!?

Romeo is chucking pebbles gently up to Juliet's window, and he wants the pebbles to hit the window with only a horizontal component of velocity. He is standing at the edge of a rose garden 8.00 meters below her window and 10.0 m from the base of the wall.

(a) How long do the pebbles take to reach the window?

(b) How fast are the pebbles going when they hit her window?

(c) What was the vertical component of the velocity of the pebble when it first leaves Romeo's hand?

(d) What was the horizontal component of the initial velocity of the pebble (when the pebble first leaves Romeo's hand)?

(e) What is the initial speed of the pebble?

(f) At what angle above the horizontal did Romeo throw the pebble?

Physics help!!?
Hi cricket lover.

a. ok - the trick is working out the time first. remember this equation... v^2 = u^2 + 2as? s = height, a = -9.81 m/s and v = 0 ... you should be able to calculate u which is the initial vertical velocity.



if you know the initial vertical velocity, you can apply v = u - gt to get the time of flight



b. if you know the time of flight and the horizontal distance, you know how fast the pebble needs to be moving towards the window.



c. you've already got that from part a.



d. the horizontal velocity doesn't change in flight, so you've got that from part b.



e. initial _speed_ = sqrt (u_vertical ^2 + u_horizontal^2)



f. angle = atan (u_vertical / u_horizontal)



this is as much as is visible of the question. hope it helps.

riding boots